The times taken by 135 runners to complete a cross-country course were recorded. The results are summarised in the table. Time (t minutes) 20<t≤30 30<t≤35 35<t≤40 40<t≤50 50<t≤70 Number of runners 15 30 40 35 15 A bag contains R red beads and B blue beads. Two beads are chosen, at random, without replacement. The tree diagram shows the possible outcomes and their probabilities. [Figure 10.1 - Tree diagram description: First bead: Red (prob 3/5), Blue (prob 2/5). Second bead (if First Red): Red (prob 11/19), Blue (prob 8/19). Second bead (if First Blue): Red (prob 12/19), Blue (prob 7/19).]
- (a)(i)On the grid, draw a histogram to represent this information.[3]
- (a)(ii)Calculate an estimate of the mean time.[3]
- (b)(i)Calculate the probability that both beads are red.[1]
- (b)(ii)Calculate the probability that the two beads are different colours.[2]
- (b)(iii)What is the value of R?[1]
- (b)(iv)Of the red beads, half have a yellow spot. Calculate the probability that, of the two chosen beads, neither has a yellow spot.[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2016). The mark or mark type is shown in brackets.
- [3] (a)(i) Correct histogram with linear scale on frequency density axis B2 for all 5 heights correct with axis scaled OR B1 for at least 3 correct frequency densities soi and B1 for all 5 bars correct widths
- [3] (a)(ii) 39.4[4...] B1 for use of correct midpoints M1 for Σfx / 135
- [1] (b)(i) 33/95 oe
- [2] (b)(ii) 48/95 oe M1 for (3/5)x(8/19) + (2/5)x(12/19) Or SC1 for answer 24/95
- [1] (b)(iii) 12 cao
- [2] (b)(iv) 91/190 oe M1 for (k / n) x ((k-1) / (n-1)) where n > k > 1
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