The distance, d metres, of a moving object from an observer after t minutes is given by d = t² + (48/t) - 20.
- (a)Some values of t and d are given in the table. The values of d are given to the nearest whole number where appropriate. Complete the table.[1]
- (b)On the grid, plot the points given in the table and join them with a smooth curve.[2]
- (c)(i)By drawing a tangent, calculate the gradient of the curve when t = 4.[2]
- (c)(ii)Explain what this gradient represents.[1]
- (d)For how long is the object less than 10 metres from the observer?[2]
- (e)(i)Using your graph, write down the two values of t when the object is 12 metres from the observer. For each value of t, state whether the object is moving towards or away from the observer.[2]
- (e)(ii)Write down the equation that gives the values of t when the object is 12 metres from the observer.[1]
- (e)(iii)This equation is equivalent to t³ + At + 48 = 0. Find A.[1]
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Mark scheme
Marking points from the official mark scheme (Oct/Nov 2015). The mark or mark type is shown in brackets.
- [1] 36
- [2] P1 for 6 correct plots ft
- Correct plots ft and curve
- [2ft] B1 for tangent at t = 4
- 4 < gradient < 6
- [1] Speed oe
- [2ft] B1 for their 1.8 and their 4.3
- Their 2.5
- [2ft] B1 for one correct ft
- Their 1.65 towards Their 4.7 away from
- [1] t² + 48/t - 20 = 12 oe isw
- [1] -32 cao
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