A group of 15 adults and 12 children are going on a coach to a concert. The tickets for the coach cost $a for each adult and $c for each child. The total cost for the coach tickets is $324.
- (a)Show that 5a + 4c = 108.[1]
- (b)For a different group of 2 adults and 3 children the cost is $53. Solve the simultaneous equations. 5a + 4c = 108; 2a + 3c = 53[4]
- (c)Find the cost for a group of 4 adults and 5 children to travel on the coach.[1]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2015). The mark or mark type is shown in brackets.
- [1] (a) 15a + 12c = 324 seen
- [4] (b) Correctly equating one set of coefficients
- [4] Correct method to eliminate one variable
- [4] Either a = 16 or c = 7 WWW
- [4] If A0, then C1 for a pair of values that satisfy either original equation.
- [4] Both a = 16 and c = 7 WWW
- [1] (c) 99;
- [1] or FT (4 × their a + 5 × their c) provided both a and c are positive
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