O-LevelComputer ScienceData Transmission2210/12 · May/June 2019 · Q93 Marks

The contents of three binary registers have been transmitted from one computer to another. Even parity has been used as an error detection method. The outcome after transmission is: Register A and Register C have been transmitted correctly. Register B has been transmitted incorrectly. Complete the Parity bit for each register to show the given outcome.

Complete the Parity bit for each register to show the given outcome. Parity bit Register A | 0 | 1 | 0 | 0 | 1 | 0 | 1 Register B | 1 | 0 | 0 | 0 | 0 | 0 | 1 Register C | 1 | 0 | 0 | 0 | 0 | 1 | 1[3]

Mark scheme

Marking points from the official mark scheme (May/June 2019). The mark or mark type is shown in brackets.

[3] 1 mark per each correct parity bit: Register A | 1 | 0 | 1 | 0 | 0 | 1 | 0 | 1 Register B | 1 | 1 | 0 | 0 | 0 | 0 | 0 | 1 Register C | 1 | 1 | 0 | 0 | 0 | 0 | 1 | 1

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Topic: Data Transmission, O-Level Computer Science (syllabus 2210). Structured question, 3 marks.
Source: O-Level Computer Science, May/June 2019 Paper 1 Variant 2, question 9.

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