The three binary numbers in the registers X, Y and Z have been transmitted from one computer to another. Parity bit Register X 1 0 0 1 0 0 1 0 Register Y 1 1 1 0 0 1 1 1 Register Z 1 1 1 0 1 0 0 1 Only one binary number has been transmitted correctly. This is identified through the use of a parity bit. Identify which register contains the binary number that has been transmitted correctly. Explain the reason for your choice. The binary number that has been transmitted correctly is in Register Explanation
- The three binary numbers in the registers X, Y and Z have been transmitted from one computer to another. Parity bit Register X 1 0 0 1 0 0 1 0 Register Y 1 1 1 0 0 1 1 1 Register Z 1 1 1 0 1 0 0 1 Only one binary number has been transmitted correctly. This is identified through the use of a parity bit. Identify which register contains the binary number that has been transmitted correctly. Explain the reason for your choice. The binary number that has been transmitted correctly is in Register Explanation[4]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2018). The mark or mark type is shown in brackets.
- [1] Register Y
- [1] Count the number of 1/0 bits (in each byte/register)
- [1] Two bytes/registers have an odd number of 1/0 bits // Two have odd parity
- [1] Even parity must be the parity used
- [1] One byte/register has an even number of 1/0 bits // One uses even parity
- [1] The two with an odd number of one bits/odd parity are incorrect // Register X and Z should have even parity
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →