The three binary numbers in the registers A, B and C have been transmitted from one computer to another. Parity bit Register A 1 0 0 1 1 0 0 0 Register B 0 1 1 0 0 1 1 1 Register C 1 0 0 1 1 0 0 1 One binary number has been transmitted incorrectly. This is identified through the use of a parity bit.
- Identify which register contains the binary number that has been transmitted incorrectly. Explain the reason for your choice. The binary number that has been transmitted incorrectly is in Register ..................................................................... Explanation ..................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................[4]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2018). The mark or mark type is shown in brackets.
- [1] Register C
- [1] Count the number of 1/0 bits (in each byte/register)
- [1] Two bytes/registers have an odd number of 1/0 bits // Two use odd parity
- [1] Odd parity must be the parity used
- [1] One byte/register has an even number of 1/0 bits // One uses even parity
- [1] One with an even number of one bits/even parity is incorrect // Register C should have odd parity
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