Farmers use chemicals to improve crop yield. Ammonium phosphate, (NH4)3PO4, is used as a fertiliser and calcium hydroxide, Ca(OH)2, is used to reduce the acidity of soils. The relative formula mass of ammonium phosphate is 149.
- (a)Calculate the percentage by mass of nitrogen in ammonium phosphate. percentage = % [1][1]
- (b)(i)A farmer adds ammonium phosphate to a field. He then adds calcium hydroxide to the field because the soil is very acidic. Calcium hydroxide neutralises the acid in the soil. Give the ionic equation for this reaction. .[1][1]
- (b)(ii)The calcium hydroxide reduces the effectiveness of the ammonium phosphate fertiliser because it reduces the nitrogen content. Explain why adding calcium hydroxide reduces the nitrogen content. ..[2][2]
- (c)(i)A sample of ammonium phosphate can be produced by the reaction of aqueous ammonia and phosphoric acid. 3NH3(aq) + H3PO4(aq) → (NH4)3PO4(aq) 25.0 cm³ of 1.25 mol/dm³ phosphoric acid is neutralised by 45.3cm³ of aqueous ammonia. Calculate the concentration, in mol/dm³, of the ammonia used. concentration of ammonia = mol/dm³ [3][3]
- (c)(ii)Show, by calculation, that 4.66g of ammonium phosphate would be produced. Assume that the yield is 100%. [Mr: (NH4)3PO4, 149] [1][1]
- (c)(iii)In practice, the actual mass of ammonium phosphate produced is 2.93g. Calculate the percentage yield of ammonium phosphate. percentage yield = % [1][1]
Mark scheme
Marking points from the official mark scheme (May/June 2014). The mark or mark type is shown in brackets.
- [1] A2 (a) 28.2 (1) ALLOW: 28
- [1] (b) (i) OH¯ + H+ → H2O (1) IGNORE: state symbols
- [1] (b) (ii) Ammonia formed (1)
- [1] (b) (ii) (Ammonia) is a gas / (ammonia) escapes into air / (ammonia) escapes from soil (1) NOTE: 2nd marking point dependent on 1st marking point being correct.
- [1] (c) (i) Mol of H3PO4 = 1.25 × 25/1000 -= 0.03125 (1) (mark for working or correct answer)
- [1] (c) (i) Moles of ammonia = 0.03125 × 3 = 0.09375 (1) (mark for working or correct answer) ALLOW: answer from 1st marking point × 3
- [1] (c) (i) Concentration of ammonia = 2.07 (1) ALLOW: answer from second marking point / 0.0453 with correctly evaluated answer
- [1] (c) (ii) Mass = 0.03125 × 149 (1) NOTE: Mark for the working out, not the answer.
- [1] (c) (iii) 62.9 (1)
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