At high temperatures, hydrogen reacts with iodine to form hydrogen iodide. H2(g) + I2(g) ⇌ 2HI(g) ΔH = + 53.0 kJ/mol
- (a)(i)Describe and explain the effect, if any, on the position of equilibrium when the pressure is increased,[2]
- (a)(ii)the temperature is decreased.[2]
- (b)(i)Hydrogen iodide reacts with water to form a strong acid, hydriodic acid, HI(aq). What is meant by the term strong acid?[1]
- (b)(ii)Construct the equation for the dissociation of hydrogen iodide molecules into ions.[1]
- (c)Hydrogen iodide reacts with ethene to form iodoethane. CH2=CH2 + HI → CH3 CH2I What is the name of this type of reaction?[1]
- (d)(i)The table shows some properties of five alkenes. alkene formula melting point /°C boiling point /°C ethene C2H4 -168.9 -103.6 propene C3H6 -47.3 butene C4H8 -185.2 -6.2 pentene C5H10 -165.0 30.0 hexene C6H12 -139.7 63.4 How does the boiling point change as the number of carbon atoms in the formula of the alkenes increases?[1]
- (d)(ii)What is the physical state of butene at −7°C? Explain your answer.[1]
- (d)(iii)Why is it difficult to predict the melting point of propene using only the information from the table?[1]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2017). The mark or mark type is shown in brackets.
- [1] No effect
- [1] Equal number of moles (of gases) on each side of the equation / each volumes (of gases) on each side of the equation
- [1] Equilibrium moves to the left
- [1] The (forward) reaction is endothermic / backward reaction exothermic / goes in the direction of the exothermic reaction
- [1] Substance which completely dissociates to form H+ ions / substance which completely ionises to form H+ ions
- [1] HI → H⁺ + I¯
- [1] Addition
- [1] Increases (as the number of C atoms increases)
- [1] Liquid because –7 °C / it is above its melting point and below its boiling point / liquid because –7 °C / it is between the melting point and boiling point
- [1] There is no clear trend / the values go up and down / the values go down and up
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