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O-LevelChemistryOrganic Chemistry5070/22 · Oct/Nov 2015 · Q211 Marks

Plants contain many different types of carbon compounds.

  1. (a)Carbon compounds are made in plants by photosynthesis. Write the overall equation for photosynthesis and state the conditions required for this process.[3]
  2. (b)(i)Starch is a polymer found in plants. Starch can be hydrolysed. Give the name of the product formed when starch is hydrolysed.[1]
  3. (b)(ii)Give the reagent and conditions needed to hydrolyse starch.[2]
  4. (c)(i)When wood chips are heated in the absence of air, a colourless distillate is formed. wood chips heat cold water distillate The distillate contains ethanoic acid, esters and other organic compounds. Ethanoic acid reacts with calcium hydroxide to form a salt and water. Give the name and formula of the salt formed. name formula[2]
  5. (c)(ii)One of the esters in the distillate has the molecular formula, C4H8O2. Draw the structure of an ester with this formula, showing all the atoms and all the bonds.[1]
  6. (c)(iii)The distillate also contains a compound with the following composition. element | percentage by mass ---|--- carbon | 37.5 hydrogen | 12.5 oxygen | 50.0 Deduce the empirical formula of this compound.[2]

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Mark scheme

Marking points from the official mark scheme (Oct/Nov 2015). The mark or mark type is shown in brackets.

  1. [3] (a) 6CO2 + 6H2O → C6H12O6 + 6O2 (2) 1 mark for correct reactants and products 1 mark for correct balancing (dependent on correct reactants and products) conditions: chlorophyll and light (1)
  2. [1] (b) (i) glucose/sugars (1)
  3. [2] (b) (ii) EITHER acid (1) heat/reflux (1) OR enzymes/amylase (1) REJECT: other named enzymes which do not hydrolyse starch at room temperature/temperature any value between 1°C and 40°C/pH 7 (1)
  4. [2] (c) (i) calcium ethanoate (1) (CH3COO)2Ca/correct displayed formula (1)
  5. [1] (c) (ii) CH3COOC2H5 shown as displayed formula (1) or C2H5COOCH3 shown as displayed formula (1) or HCOOC3H7 shown as displayed formula (1) or HCOOCH(CH3)2 shown as displayed formula (1)
  6. [2] (c) (iii) 1 mark for C = 37.5/12 or = 3.125 H = 12.5/1 = 12.5 O = 50/16 = 3.125 1 mark for 3.125 3.125 3.125 or 1 4 1 or CH4O

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About this question

Topic
Organic Chemistry, O-Level Chemistry (syllabus 5070). Structured question, 11 marks.
Source
O-Level Chemistry, Oct/Nov 2015 Paper 2 Variant 2, question 2.

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