When 1 mole of sodium hydroxide reacts with excess hydrochloric acid, 57.1 kJ of energy is released. NaOH + HCl → NaCl + H₂O
- (a)Calculate the energy released when 12.0g of sodium hydroxide reacts with excess hydrochloric acid.[2]
- (b)Calculate the volume of 0.200mol/dm³ HCl which contains 2.19g of HCl.[2]
- (c)Aqueous hydrochloric acid contains chloride ions. Describe a test for chloride ions. test result[2]
- (d)Zinc oxide reacts with both hydrochloric acid and sodium hydroxide. Which term describes this behaviour of zinc oxide?[1]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2015). The mark or mark type is shown in brackets.
- [2] A6 (a) mol of NaOH = 0.30 (1) energy released (= 0.30 × 57.1) = 17/17.1(3) (kJ) (1)
- [2] (b) mol of HCl = 2.19/36.5 OR = 0.06 (1) volume = (0.06/0.2) = 0.3 dm³/300 cm³ (1)
- [2] (c) add nitric acid and silver nitrate (1) white precipitate/white solid formed (1)
- [1] (d) amphoteric (1)
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