A student titrates 20.0 cm³ of a metal hydroxide, M(OH)2, of concentration 0.060mol/dm³ with a strong acid of concentration 0.050mol/dm³. It requires 24.0cm³ of acid to neutralise the metal hydroxide.
- (a)(i)Calculate the number of moles of acid in 24.0cm³ of the acid. moles[1]
- (a)(ii)Calculate the number of moles of OH¯ ions in 20.0cm³ of the metal hydroxide. moles[1]
- (a)(iii)Deduce whether the acid used is more likely to be hydrochloric acid or sulfuric acid. Explain your answer.[1]
- (b)A student added excess calcium carbonate to 50 cm³ of 0.10mol/dm³ hydrochloric acid.
- (b)(i)Construct an equation for the reaction of calcium carbonate with hydrochloric acid.[1]
- (b)(ii)The volume of gas produced in the first 2 minutes is 24 cm³. Calculate the average rate of reaction over the first 2 minutes, in cm³/s. reaction rate = .cm³/s[1]
- (b)(iii)The student repeats the experiment using 50 cm³ of 0.10mol/dm³ ethanoic acid. Use the kinetic particle theory to explain why the rate of reaction is slower with ethanoic acid than with hydrochloric acid.[3]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2014). The mark or mark type is shown in brackets.
- [1] (a)(i) moles acid = 1.2 × 10¯³/0.0012 mol (1)
- [1] (a)(ii) moles OH¯ ions = 2.4 × 10¯³/0.0024 mol (1)
- [1] (a)(iii) sulfuric (acid) (no mark but if incorrect 0, marks for question) mole ratio of acid to OH¯ is 1:2 so the acid must have 2H⁺ per mole/only way to get 1:1 ratio of H⁺ to OH from 1:2 ratio of acid to OH (1)
- [1] (b)(i) CaCO3 + 2HCl → CaCl2 + CO2 + H2O (1)
- [1] (b)(ii) 24/(2 × 60) = 0.2cm³/s (1)
- [3] (b)(iii) ethanoic acid dissociates only slightly/ethanoic acid partially dissociated/hydrochloric acid dissociated fully (1) lower concentration of H⁺ ions in ethanoic acid OR reverse argument (1) lower frequency of collisions (with CaCO3) in ethanoic acid OR reverse argument (1)
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