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O-LevelBiologyGenetics & Variation5090/22 · May/June 2019 · Q312 Marks

The diagram shows the internal structure of a seed from a pea plant. [Figure 3.1: Internal structure of a seed from a pea plant with parts C, D, E, F labeled.] Seeds from a pea plant are non-endospermic.

  1. (a)Identify each of parts C to F. C D E F[4]
  2. (b)(i)Name the part of a cell that contains the genes.[1]
  3. (b)(ii)Define each of the following terms: gene dominant allele[4]
  4. (b)(iii)One pea plant, H, has a homozygous genotype that develops seeds with a wrinkled surface. Another pea plant, J, has an unknown genotype. When these two plants were cross-pollinated, approximately half of the new plants produced had peas with a wrinkled surface. Complete the genetic diagram below for this cross and state the genotype of pea plant J. gametes of pea plant H (r) (r) gametes of R Rr Rr pea plant J r rr rr genotype of pea plant J:[3]

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Mark scheme

Marking points from the official mark scheme (May/June 2019). The mark or mark type is shown in brackets.

  1. [4] (C) testa / seed coat ;
  2. [4] (D) plumule;
  3. [4] (E) radicle;
  4. [4] (F) cotyledon(s);
  5. [1] nucleus / chromosome(s) / DNA ;
  6. [4] gene: made of DNA / section of a chromosome;
  7. [4] gene: copied / passed on / inherited / hereditary ;
  8. [4] gene: one AW + characteristic / trait / protein / polypeptide ;
  9. [4] dominant allele: version / form / type + of a gene ;
  10. [4] dominant allele: expressed AW + always / if only one copy present / by heterozygote / over another allele;
  11. [3] Punnett Square (correctly filled as shown in QP, with Rr in top row, rr in bottom row for offspring, and R, r as gametes for plant J);
  12. [3] genotype of pea plant J: Rr / heterozygous ;

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About this question

Topic
Genetics & Variation, O-Level Biology (syllabus 5090). Structured question, 12 marks.
Source
O-Level Biology, May/June 2019 Paper 2 Variant 2, question 3.

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