Find the exact value of ∫₀² 6e²ˣ⁺¹ dx.
- (a)Find the exact value of ∫₀² 6e²ˣ⁺¹ dx.[3]
- (b)Find ∫ (tan²x + 4 sin² 2x) dx.[5]
Mark scheme
Marking points from the official mark scheme (May/June 2021). The mark or mark type is shown in brackets.
- [M1] Integrate to obtain form ke²ˣ⁺¹
- [A1] Obtain correct 3e²ˣ⁺¹
- [A1] Apply limits correctly to obtain 3e⁵ - 3e
- [B1] State tan²x = sec²x - 1
- [M1] Express 4sin²2x in the form k₁ + k₂cos4x
- [A1] Obtain correct 2 - 2cos 4x
- [M1] Integrate to obtain form k₃tan x + k₄x + k₅sin 4x
- [A1] Obtain correct tan x + x - (1/2)sin 4x
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