The length of time, T minutes, that a passenger has to wait for a bus at a certain bus stop is modelled by the probability density function given by f(t) = { (3/4000)(20t - t²) 0 ≤ t ≤ 20, 0 otherwise.
- (a)Sketch the graph of y = f(t).[1]
- (b)Hence explain, without calculation, why E(T) = 10.[1]
- (c)Find Var(T).[3]
- (d)It is given that P(T < 10 + a) = p, where 0 < a < 10. Find P(10 – a < T < 10 + a) in terms of p.[2]
- (e)Find P(8 < T < 12).[3]
- (f)Give one reason why this model may be unrealistic.[1]
Mark scheme
Marking points from the official mark scheme (May/June 2020). The mark or mark type is shown in brackets.
- [B1] 'Tails down' parabola only from x = 0 to 20 shown
- [B1] Symmetrical
- [M1] 3/4000 ∫(20t³ - t⁴)dx evaluated for E(T²)
- [M1] Var(T) = (3/4000)×160000-10²
- [A1] 20
- [M1] (p-0.5)×2 or 1-2(1-p)
- [A1] 2p-1
- [M1] 3/4000 ∫₁₂⁸ (20t-t²)dt
- [A1] [3/4000 * (10t² - t³/3)] evaluated from 8 to 12
- [A1] 37/125 or 0.296
- [B1] Does not allow times greater than 20 minutes
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