Two machines, A and B, produce metal rods of a certain type. The lengths, in metres, of 19 rods produced by machine A and 19 rods produced by machine B are shown in the following back-to-back stem-and-leaf diagram. ``` A | | B 7 6 3 0 | 21 | 1 2 4 8 7 4 3 1 1 | 22 | 2 4 5 5 6 5 5 5 3 2 | 23 | 0 2 6 8 9 9 4 3 1 0 | 24 | 3 3 4 6 | 25 | 6 ``` Key: 7 | 22 | 4 means 0.227 m for machine A and 0.224 m for machine B.
- (a)Find the median and the interquartile range for machine A.[3]
- (b)It is given that for machine B the median is 0.232m, the lower quartile is 0.224 m and the upper quartile is 0.243 m. Draw box-and-whisker plots for A and B.[3]
- (c)Hence make two comparisons between the lengths of the rods produced by machine A and those produced by machine B.[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2020). The mark or mark type is shown in brackets.
- [B1] Median = 0.238
- [M1] UQ = 0.245, LQ=0.231, So IQR = 0.245 – 0.231
- [A1] 0.014
- [B1] Medians and quartiles correctly plotted for A or B
- [B1] End points correct for A or B
- [B1] Completely correct, including scale
- [B1] Lengths of rods produced by machine A are longer. (B1 for comparison of central tendency)
- [B1] Lengths of rods produced by machine A are less spread out (B1 for comparison of spread)
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