A particle P is projected vertically upwards with speed 5 m s⁻¹ from a point A which is 2.8 m above horizontal ground.
- (a)Find the greatest height above the ground reached by P.[3]
- (b)Find the length of time for which P is at a height of more than 3.6 m above the ground.[4]
Mark scheme
Marking points from the official mark scheme (May/June 2020). The mark or mark type is shown in brackets.
- [M1] 0 = 5² - 2gs
- [A1] s = 1.25
- [A1] [Height above ground =] 4.05 m
- [M1] Use of s = ut + ½ at²
- [A1] 0.8 = 5t - 5t²
- [M1] t = 0.2 or 0.8
- [A1] Length of time = 0.6 s
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