A certain curve is such that its gradient at a point (x, y) is proportional to y / (x√x). The curve passes through the points with coordinates (1, 1) and (4, e).
- (a)By setting up and solving a differential equation, find the equation of the curve, expressing y in terms of x.[8]
- (b)Describe what happens to y as x tends to infinity.[1]
Mark scheme
Marking points from the official mark scheme (May/June 2020). The mark or mark type is shown in brackets.
- [B1] (a) State dy/dx = k y / (x√x), or equivalent
- [M1] (a) Separate variables correctly and attempt integration of at least one side
- [A1] (a) Obtain term ln y, or equivalent
- [A1] (a) Obtain term -2k/√x, or equivalent
- [M1] (a) Use given coordinates to find k or a constant of integration c in a solution containing terms of the form a ln y and b/√x, where ab ≠ 0
- [A1 + A1] (a) Obtain k = 1 and c = 2
- [A1] (a) Obtain final answer y = exp(-2/√x + 2), or equivalent
- [B1FT] (b) State that y approaches e² (FT their c in part (a) of the correct form)
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →