Particles P and Q leave a fixed point A at the same time and travel in the same straight line. The velocity of P after t seconds is 6t(t − 3) m s⁻¹ and the velocity of Q after t seconds is (10 – 2t) m s⁻¹.
- (i)Sketch, on the same axes, velocity-time graphs for P and Q for 0 ≤ t ≤ 5.[3]
- (ii)Verify that P and Q meet after 5 seconds.[4]
- (iii)Find the greatest distance between P and Q for 0 ≤ t ≤ 5.[4]
Mark scheme
Marking points from the official mark scheme (May/June 2019). The mark or mark type is shown in brackets.
- [B1] Straight line, reaching positive v-axis and positive t-axis (negative gradient)
- [B1] Quadratic (U shape, through (0,0) and cutting t-axis at t < 5)
- [B1] Fully correct graphs with correct labelling with t = 3, t = 5, v = 10, v = 60 seen
- [B1] Use either integration to find s for Q or use a correct formula to find the area under the relevant triangle
- [M1] Use integration to find the displacement for P
- [A1] Correct integration for P (unsimplified)
- [B1] Either evaluation of s(P) at t = 5 and show that at t = 5, s(P) = s(Q) = 25 or show that t = 5 is a solution of the cubic by solving or verify t = 5 is a solution of the cubic by substitution.
- [M1] Find the distance between P and Q Allow either sign s_P and s_Q must have been found by integration
- [M1] Differentiate to obtain an equation in t and attempt to solve
- [A1]
- [A1] Maximum Distance PQ = (-)48.4 m
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →