A-LevelMathematicsTrigonometry9709/32 · May/June 2019 · Q35 Marks
Showing all necessary working, solve the equation cot 2θ = 2 tan θ for 0° < θ < 180°.
- Showing all necessary working, solve the equation cot 2θ = 2 tan θ for 0° < θ < 180°.[5]
Mark scheme
Marking points from the official mark scheme (May/June 2019). The mark or mark type is shown in brackets.
- [*M1] Use correct trig formulae to obtain an equation in tan θ or equivalent (e.g. all in sin θ or all in cos θ) (1-tan²θ)/(2tanθ) = 2tanθ. Allow (cot²θ-1)/(2cotθ) = 2/cotθ
- [A1] Obtain a correct simplified equation (5tan²θ = 1 or sin²θ = 1/6 or cos²θ = 5/6)
- [DM1] Solve for θ (Dependent on the first M1)
- [A1] Obtain answer 24.1° (or 155.9°) (One correct in range to at least 3 sf)
- [A1] Obtain second answer (FT 180° – their 24.1° and no others in range. Correct to at least 3 sf. Accept 156° but not 156.0. Ignore values outside range. If working in tanθ or cosθ need to be considering both square roots to score the second A1. Mark 0.421, 2.72 as a MR, so A0A1)
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