The diagram shows a set of rectangular axes Ox, Oy and Oz, and four points A, B, C and D with position vectors **OA** = 3**i**, **OB** = 3**i** + 4**j**, **OC** = **i** + 3**j** and **OD** = 2**i** + 3**j** + 5**k**.
- (i)Find the equation of the plane BCD, giving your answer in the form ax + by + cz = d.[6]
- (ii)Calculate the acute angle between the planes BCD and OABC.[4]
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Mark scheme
Marking points from the official mark scheme (May/June 2019). The mark or mark type is shown in brackets.
- [B1] (i) Obtain a vector parallel to the plane, e.g. CB = 2i + j
- [M1] (i) Use scalar product to obtain an equation in a, b, c, e.g. 2a + b = 0, a + 5c = 0, a + b − 5c = 0
- [A1] (i) Obtain two correct equations in a, b, c
- [M1] (i) Solve to obtain a : b : c,
- [A1] (i) Obtain a:b: c = 5 : - 10 : – 1, or equivalent
- [A1] (i) Obtain equation 5x-10y - z = -25, or equivalent
- [B1] (i) Obtain a vector parallel to the plane, e.g. CD = i + 5k
- [M1] (i) Obtain a second such vector and calculate their vector product, e.g. (2i+j)×(i+5k)
- [A1] (i) Obtain two correct components
- [A1] (i) Obtain correct answer, e.g. 5i – 10j – k
- [M1] (i) Substitute to find d
- [A1] (i) Obtain equation 5x-10y - z = -25, or equivalent
- [B1] (ii) State or imply a normal vector for the plane OABC is k
- [M1] (ii) Carry out correct process for evaluating a scalar product of two relevant vectors, e.g. (5i – 10j – k).(k)
- [M1] (ii) Using the correct process for calculating the moduli, divide the scalar product by the product of the moduli and evaluate the inverse cosine of the result
- [A1] (ii) Obtain answer 84.9° or 1.48 radians
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