A curve is such that dy/dx = x^3 - 4/x^2. The point P (2, 9) lies on the curve.
- (i)A point moves on the curve in such a way that the x-coordinate is decreasing at a constant rate of 0.05 units per second. Find the rate of change of the y-coordinate when the point is at P.[2]
- (ii)Find the equation of the curve.[3]
Mark scheme
Marking points from the official mark scheme (May/June 2019). The mark or mark type is shown in brackets.
- [M1] Multiply numerical gradient at x = 2 by ±0.05.
- [A1] -0.35 (units/s) or Decreasing at a rate of (+) 0.35
- [B1] (y =) x^4/4 + 4/x (+c) oe
- [M1] The power of at least one term increase by 1.
- [A1] c = 3 or (y =) x^4/4 + 4/x + 3 oe
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