A small ball B is projected from a point O on horizontal ground. The initial velocity of B has horizontal and vertically upwards components of 18ms¯¹ and 25 ms¯¹ respectively. For the instant 4s after projection, find the speed and direction of motion of B.
- A small ball B is projected from a point O on horizontal ground. The initial velocity of B has horizontal and vertically upwards components of 18ms¯¹ and 25 ms¯¹ respectively. For the instant 4s after projection, find the speed and direction of motion of B.[4]
Mark scheme
Marking points from the official mark scheme (May/June 2018). The mark or mark type is shown in brackets.
- [M1] Vertical component of velocity = 25 - 4g; Use v = u + at
- [M1] v² = 18² + (25-4g)² or tanθ = (25-4g)/18
- [A1] v = 23.4 ms⁻¹
- [A1] θ = 39.8° below the horizontal
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