A-LevelMathematicsMechanics9709/43 · May/June 2018 · Q15 Marks

The diagram shows the velocity-time graph for a train which travels from rest at one station to rest at the next station. The graph consists of three straight line segments. The distance between the two stations is 9040 m. [Figure 1.1]

(i)Find the acceleration of the train during the first 40 s.[1]
(ii)Find the length of time for which the train is travelling at constant speed.[2]
(iii)Find the distance travelled by the train while it is decelerating.[2]

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Mark scheme

Marking points from the official mark scheme (May/June 2018). The mark or mark type is shown in brackets.

[B1] 0.4 (m s⁻²)
[M1] [9040 = ½(600+T)×16] Equating area of the trapezium to the total distance or using s = ½ (u + v)t or equivalent
[A1] Time is 530 (s)
[M1] [s=½×(600-530-40)×16] Use of triangular area, or equivalent
[A1] Distance is 240 (m)

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Topic: Mechanics, A-Level Mathematics (syllabus 9709). Structured question, 5 marks.
Source: A-Level Mathematics, May/June 2018 Paper 4 Variant 3, question 1.

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