The following histogram represents the lengths of worms in a garden. [Figure X.X]
- (i)Calculate the frequencies represented by each of the four histogram columns.[2]
- (ii)On the grid on the next page, draw a cumulative frequency graph to represent the lengths of worms in the garden.[4]
- (iii)Use your graph to estimate the median and interquartile range of the lengths of worms in the garden.[3]
- (iv)Calculate an estimate of the mean length of worms in the garden.[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2017). The mark or mark type is shown in brackets.
- [M1] freq = fd × cw 10, 40, 120, 30 Attempt to multiply at least 3 fds by their 'class widths'
- [A1]
- [B1] length <5 <10 <20 <25, cf 10 50 170 200 3 or more correct cfs heights on graph 10, 50, 170, 200
- [B1] Labels correct cf and length(cm), linear scales from zero (allow 0.5 on horizontal axis)
- [M1] Attempt (at least three) at plotting at upper end points (either 5 or 5.5, 10 or 10.5 etc.)
- [A1] Starting at (0, 0) polygon or smooth curve increasing with plotted points at lengths 5, 10, 20 and 25
- [B1] median = 14.2 Median (accept 13.2 – 15.2)
- [M1] '18.5'- '10' Subt their LQ from their UQ if reasonable from their graph
- [A1FT] IQ range = 8.5 Correct FT using LQ = 10 and UQ between 17.5 and 19.5
- [M1] mean = (2.5×10 +7.5×40 + 15×120 +22.5×30) / 200 Using mid points (± 0.5) and their frequencies from 7(i) in correct formula
- [A1] = 14
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