In a probability distribution the random variable X takes the value x with probability kx², where k is a constant and x takes values −2, −1, 2, 4 only.
- (i)Show that P(X = −2) has the same value as P(X = 2).[1]
- (ii)Draw up the probability distribution table for X, in terms of k, and find the value of k.[3]
- (iii)Find E(X).[2]
Mark scheme
Marking points from the official mark scheme (May/June 2017). The mark or mark type is shown in brackets.
- B1 need to see –2² k, 22k and 4k, algebraically correct expressions OE
- B1 -2, -1, 2, 4 only seen in a table, together with at least one attempted probability involving k
- M1 Summing 4 probs equating to 1. Must all be positive (table not required)
- A1 CWO
- M1 using Epx unsimplified. FT their k substituted before this stage, no inappropriate dividing
- A1
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →