A man pushes a wheelbarrow of mass 25 kg along a horizontal road with a constant force of magnitude 35 N at an angle of 20° below the horizontal. There is a constant resistance to motion of 15 N. The wheelbarrow moves a distance of 12 m from rest.
- (i)Find the work done by the man.[2]
- (ii)Find the speed attained by the wheelbarrow after 12 m.[3]
Mark scheme
Marking points from the official mark scheme (May/June 2017). The mark or mark type is shown in brackets.
- M1 Uses WD = Fd cos 0
- A1 395 J
- (B1 WD against resistance = 15 × 12
- M1 Uses WDman = WDresistance + KE gain
- A1) v = 4.14 ms⁻¹
- (B1 Applies Newton's Second Law
- M1 Uses v² = u² + 2as
- A1) v = 4.14 ms⁻¹
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