Throughout this question the use of a calculator is not permitted. The complex number 2 – i is denoted by u.
- (i)It is given that u is a root of the equation x³ + ax² – 3x + b = 0, where the constants a and b are real. Find the values of a and b.[4]
- (ii)On a sketch of an Argand diagram, shade the region whose points represent complex numbers z satisfying both the inequalities |z – u| < 1 and |z| < |z + i|.[4]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2017). The mark or mark type is shown in brackets.
- [M1] Substitute x = 2 – i (or x = 2+i ) in the equation and attempt expansions of x² and x³
- [M1] Equate real and/or imaginary parts to zero
- [A1] Obtain a = -2
- [A1] Obtain b = 10
- [M1] Substitute x = 2 – i in the equation and attempt expansions of X² and x³
- [M1] Substitute x=2+i in the equation and add/subtract the two equations
- [A1] Obtain a = -2
- [A1] Obtain b = 10
- [M1] Factorise to obtain (x−2+i)(x-2-1)(x-p) (= (x²-4x+5)(x-p))
- [M1] Compare coefficients
- [A1] Obtain a = -2
- [A1] Obtain b = 10
- [M1] Obtain the quadratic factor (x² - 4x+5)
- [M1] Use algebraic division to obtain a real linear factor of the form x-p and set the remainder equal to zero
- [A1] Obtain a = -2
- [A1] Obtain b = 10
- [M1] Use aβ = 5 and a + β =4 in αβ + βγ + γα = −3
- [M1] Solve for γ and use in αβγ = −b and/or α + β + γ = -a
- [A1] Obtain a = -2
- [A1] Obtain b = 10
- [M1] Factorise as (x-- (2-i))(x² + ex + g) and compare coefficients to form an equation in a and b
- [M1] Equate real and/or imaginary parts to zero
- [A1] Obtain a = -2
- [A1] Obtain b = 10
- [B1] Show a circle with centre 2 – i in a relatively correct position
- [B1] Show a circle with radius 1 and centre not at the origin
- [B1] Show the perpendicular bisector of the line segment joining 0 to – i
- [B1] Shade the correct region
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