The diagram shows the curve with equation y = 3x² ln((1/2)x). The curve crosses the x-axis at the point P and has a minimum point M. [Figure 8]
- (i)Find the gradient of the curve at the point P.[5]
- (ii)Find the exact coordinates of the point M.[5]
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Mark scheme
Marking points from the official mark scheme (May/June 2017). The mark or mark type is shown in brackets.
- [*M1] Apply product rule to find first derivative
- [A1] Obtain 6xln((1/2)x)+3x or equivalent
- [B1] Identify x = 6 at P
- [DM1] Substitute their value of x at P into attempt at first derivative
- [A1] Obtain 18
- [*M1] Equate their first derivative to zero and attempt solution of equation of form kln((1/2)x)+m=0
- [DM1] Obtain x-coordinate of form ae^(b)
- [A1] Obtain x = 6e⁻¹ or exact equivalent
- [M1] Substitute exact x-value in the form a₂e^(b) and attempt simplification to remove ln
- [A1] Obtain -54e⁻¹ or exact equivalent
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