Given that ∫₀ᵃ 4e^(2x+3) dx = 835, find the value of the constant a correct to 3 significant figures.
- Given that ∫₀ᵃ 4e^(2x+3) dx = 835, find the value of the constant a correct to 3 significant figures.[5]
Mark scheme
Marking points from the official mark scheme (May/June 2017). The mark or mark type is shown in brackets.
- [M1] Integrate to obtain form ke^(2x+3) where k is constant not equal to 4
- [A1] Obtain correct 8e^(2x+3)
- [A1] Obtain 8e^(2a+3) - 8e³ = 835 or equivalent
- [M1] Carry out correct process to find a from equation of form ke^(ma+c) = d
- [A1] Obtain 3.65
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