Relative to an origin O, the position vectors of points A and B are given by OA = 2i + 4j + 4k and OB = 3i + j + 4k.
- (i)Use a vector method to find angle AOB.[4]
- (ii)The point C is such that AB = BC. Find the unit vector in the direction of OC.[4]
- (iii)Show that triangle OAC is isosceles.[1]
Mark scheme
Marking points from the official mark scheme (May/June 2015). The mark or mark type is shown in brackets.
- [M1] (i) OA . OB = 6 + 4 + 16 = 26 Must be numerical at some stage
- [M1] (i) |OA| = √36, |OB| = √26 Product of 2 moduli
- [M1] (i) Cos AOB = 26 / (6√26) All linked correctly
- [A1] (i) → 31.8° co
- [B1] (ii) AB = b – a = (1 -3 0)
- [M1] (ii) OC = OA + 2AB or OB + AB Correct link
- [M1 A1] (ii) Unit vector ÷ modulus → (1/6)(4 -2 4) ÷ by modulus. co
- [B1] (iii) |OC| = 6, |OA| = 6 co
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