The coefficient of x³ in the expansion of (a + x)⁵ + (2 – x)⁶ is 90. Find the value of the positive constant a.
- The coefficient of x³ in the expansion of (a + x)⁵ + (2 – x)⁶ is 90. Find the value of the positive constant a.[5]
Mark scheme
Marking points from the official mark scheme (May/June 2012). The mark or mark type is shown in brackets.
- [B1 B1] Coeff of x³ in (a+x)⁵ = ¹⁰C₂ a² = 10a² (or ¹⁰C₃ a²x³); co co (for 10 and a²).
- [B1] Coeff of x³ in (2−x)⁶ = ⁶C₃ (2)³ (-x)³ = -160; co
- [M1] Sum of coefficients = 10a² - 160 = 90; forms an equation from 2 terms.
- [A1] → a = 5; co
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →