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A-LevelMathematicsFunctions9709/12 · May/June 2011 · Q98 Marks

The function f is such that f(x) = 3 – 4 cosᵏx, for 0 ≤ x ≤ π, where k is a constant.

  1. (i)(a)find the range of f,[2]
  2. (i)(b)find the exact solutions of the equation f(x) = 1.[3]
  3. (ii)(a)sketch the graph of y = f(x),[2]
  4. (ii)(b)state, with a reason, whether f has an inverse.[1]

Mark scheme

Marking points from the official mark scheme (May/June 2011). The mark or mark type is shown in brackets.

  1. [2] (i)(a) f(x) = 3 - 4cos²x.; B1 co irrespective of inequalities; B1 co irrespective of inequalities; One limit is -1; Other limit is 3
  2. [3] (i)(b) 3 - 4cos²x = 1 → cos²x = ½; M1 Makes cos x the subject.; → cosx = ±1/√2; A1 A1√ co (radians). √ for “π – (1st answer)” ("exact" means that decimal answers only earn A0 A1√); → x = ¼π or ¾π
  3. [2] (ii)(a); B1 Joins (0, -1) to (π, 7), providing increasing function; B1 Not a line, flattens at extremities-needs inflexion.
  4. [1] (ii)(b) f has an inverse since it is 1:1 or increasing or no turning points.; B1 co independent of part (i)

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About this question

Topic
Functions, A-Level Mathematics (syllabus 9709). Structured question, 8 marks.
Source
A-Level Mathematics, May/June 2011 Paper 1 Variant 2, question 9.

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