A geometric progression is such that its second term is – 120 and its sum to infinity is 160.
- (a)Find the common ratio.[4]
- (b)The first nine terms of the progression are now removed. Find the sum to infinity of the remaining terms of the progression.[3]
Mark scheme
Marking points from the official mark scheme (Feb/Mar 2025). The mark or mark type is shown in brackets.
- [B1] ar = -120 and a/(1-r) = 160
- [M1] (-120/r) / (1-r) = 160 or r / (1-r) * (-120/r) = 160 Elimination of either a or r. Condone ± errors for this mark.
- [A1] 4r² - 4r - 3[=0] or a² - 160a - 19200[=0] OE Rearrange to arrive at a three-term quadratic.
- [A1] r = -1/2 only
- [B1] [a =] 240 FT -120÷(their r), where -1<r<1, r≠0.
- [M1] 160 - 240(1-(-1/2)⁹) / (1-(-1/2)) With (their 240) and (their r) as long as -1<r<1, r≠0. Condone reversed subtraction.
- [A1] 5/16 or -0.3125 A0 for -0.313 without sight of -5/16 or -0.3125. Condone use of r = 3/2 to provide a second solution.
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