The diagram shows a circle with centre O and radius r. The angle of the minor sector AOB of the circle is x radians. The area of the major sector of the circle is 3 times the area of the shaded region. [Figure 7.1]
- (a)Show that x = ¾ sin x + ½π.[4]
- (b)Show by calculation that the root of the equation in (a) lies between 2 and 2.5.[2]
- (c)Use an iterative formula based on the equation in (a) to calculate this root correct to 2 decimal places. Give the result of each iteration to 4 decimal places.[3]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Feb/Mar 2023). The mark or mark type is shown in brackets.
- [B1] State or imply area of major sector = ½r²(2π – x) OE
- [B1] State or imply area of shaded segment = ½r²x - ½r² sin x OE
- [M1] State ½r²(2π – x) = 3(½r²x - ½r² sin x) OE
- [A1] Obtain the given answer x = ¾ sin x + ½π after full and correct working AG Allow rectified slip if before penultimate line.
- [M1] Calculate the values of a relevant expression or pair of expressions at x = 2 and x = 2.5
- [A1] Complete the argument correctly with correct calculated values Degrees award 0/2
- [M1] Use the iterative formula correctly at least twice
- [A1] Obtain final answer 2.18
- [A1] Show sufficient iterations to 4 d.p. to justify 2.18 to 2 d.p. or show there is a sign change in the interval (2.175, 2.185) Degrees award 0/3
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →