A particle of mass 0.6 kg is placed on a rough plane which is inclined at an angle of 21° to the horizontal. The particle is kept in equilibrium by a force of magnitude P N acting parallel to a line of greatest slope of the plane, as shown in the diagram. The coefficient of friction between the particle and the plane is 0.3. Show that the least possible value of P is 0.470, correct to 3 significant figures, and find the greatest possible value of P. [Figure 3]
- Show that the least possible value of P is 0.470, correct to 3 significant figures, and find the greatest possible value of P.[6]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Feb/Mar 2017). The mark or mark type is shown in brackets.
- [B1] R = 0.6g cos 21 [= 5.60]
- [M1] Using F = μR
- [M1] Slipping down
- [A1] Least possible value P = 2.15-1.68 = 0.470 AG
- [M1] Slipping up
- [A1] Greatest possible value P=2.15 +1.68 = 3.83
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