The equation of a curve is such that dy/dx = kx³ + 2/x², where k is a constant. The curve passes through the point S (2, 20) and the gradient of the curve at S is 65/2.
- (a)Find the value of k.[1]
- (b)The coordinates of a point T on the curve are (1, t). Find the value of t.[5]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2025). The mark or mark type is shown in brackets.
- [B1] k = 4
- [B2] Integrates dy/dx to y = (kx^4)/4 - 2/x [+c] (B1 for one term correct).
- [M1] Substitutes x=2, y=20 into their integrated expression to find c.
- [A1] c = 5.
- [A1] t = 4.
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