A random variable X has probability density function f defined by f(x) = { a/x² - 18/x³ for 2 ≤ x ≤ 3, 0 otherwise, where a is a constant.
- (a)Show that a = 27/2.[3]
- (b)Show that E(X) = 27/2 ln(3/2) - 3.[3]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2024). The mark or mark type is shown in brackets.
- [M1] ∫ (a/x² - 18/x³) dx = 1 Attempt integrate f(x), ignore limits and ‘= 1'.
- [A1] [-a/x + 9/x²] from 2 to 3 = 1 OE Correct integration and limits.
- [A1] [-a/3 + 9/9] - [-a/2 + 9/4] = 1 a = 27/2 (AG) Must see correct substitution of limits. Correct working no errors seen.
- [M1] ∫ x(a/x² - 18/x³) dx Attempt to integrate xf(x), ignore limits.
- [A1] [a ln x + 18/x] from 2 to 3 or [a ln 2x + 18/x] from 2 to 3 OE e.g. using In 2x.
- [A1] = 27/2 ln 3 + 6 - (27/2 ln 2 + 9) = 27/2 ln 3/2 - 3 AG Must see correct substitution of limits. Correct working no errors seen.
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →