Let f(x) = 7a² / ((a-2x)(3a+x)), where a is a positive constant.
- (a)Express f(x) in partial fractions.[3]
- (b)Hence obtain the expansion of f(x) in ascending powers of x, up to and including the term in x².[4]
- (c)State the set of values of x for which the expansion in part (b) is valid.[1]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2024). The mark or mark type is shown in brackets.
- [M1] (a) State or imply the form A/(a-2x) + B/(3a+x) and use a correct method to find a constant.
- [A1] (a) Obtain A=2a or B = a.
- [A1] (a) Obtain A=2a and B = a.
- [M1] (b) Use a correct method to obtain the first two terms of the expansion of (a-2x)⁻¹ or (1-2x/a)⁻¹ or (3a+x)⁻¹ or (1+x/3a)⁻¹.
- [A1ft] (b) Obtain 2(1 + 2x/a + 4x²/a²) + 1/3(1 - x/3a + x²/9a²) + ... (Follow their A, B for an expansion involving a).
- [A1] (b) Obtain 7/3 + 35x/(9a) + 217x²/(27a²). Or simplified equivalent. Final answer.
- [B1] (c) |x| < a/2. Or -a/2 < x < a/2.
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