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A-LevelMathematicsSeries9709/33 · Oct/Nov 2024 · Q88 Marks

Let f(x) = 7a² / ((a-2x)(3a+x)), where a is a positive constant.

  1. (a)Express f(x) in partial fractions.[3]
  2. (b)Hence obtain the expansion of f(x) in ascending powers of x, up to and including the term in x².[4]
  3. (c)State the set of values of x for which the expansion in part (b) is valid.[1]

Mark scheme

Marking points from the official mark scheme (Oct/Nov 2024). The mark or mark type is shown in brackets.

  1. [M1] (a) State or imply the form A/(a-2x) + B/(3a+x) and use a correct method to find a constant.
  2. [A1] (a) Obtain A=2a or B = a.
  3. [A1] (a) Obtain A=2a and B = a.
  4. [M1] (b) Use a correct method to obtain the first two terms of the expansion of (a-2x)⁻¹ or (1-2x/a)⁻¹ or (3a+x)⁻¹ or (1+x/3a)⁻¹.
  5. [A1ft] (b) Obtain 2(1 + 2x/a + 4x²/a²) + 1/3(1 - x/3a + x²/9a²) + ... (Follow their A, B for an expansion involving a).
  6. [A1] (b) Obtain 7/3 + 35x/(9a) + 217x²/(27a²). Or simplified equivalent. Final answer.
  7. [B1] (c) |x| < a/2. Or -a/2 < x < a/2.

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About this question

Topic
Series, A-Level Mathematics (syllabus 9709). Structured question, 8 marks.
Source
A-Level Mathematics, Oct/Nov 2024 Paper 3 Variant 3, question 8.

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