The parametric equations of a curve are x = tan²2t, y = cos 2t, for 0 < t < ¼π.
- (a)Show that dy/dx = -½ cos³2t.[4]
- (b)Hence find the equation of the normal to the curve at the point where t = π/8. Give your answer in the form y = mx+c.[4]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2024). The mark or mark type is shown in brackets.
- [M1] Use correct product rule or chain rule to find derivative of x with respect to t
- [A1] Obtain dx/dt = 4 tan 2t sec² 2t oe
- [B1] Obtain dy/dt = -2 sin 2t
- [B1] Use dy/dx = (dy/dt) / (dx/dt) to obtain given answer dy/dx = -½ cos³ 2t
- [B1] Obtain x = 1 and y = √2/2
- [B1] State or imply gradient of tangent is -√2/8 or gradient of normal is 4√2
- [M1] Use correct method to find equation of normal using their values
- [A1] Obtain equation of normal is y = 4√2x - 7√2/2 or equivalent 3 term equation
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