Use the iterative formula x_n+1 = exp(2+e-0.2x_n) - 1 to determine the root correct to 2 decimal places. Give the result of each iteration to 4 decimal places. [exp(x) is an alternative notation for eˣ.]
- (c)Use the iterative formula x_n+1 = exp(2+e-0.2x_n) - 1 to determine the root correct to 2 decimal places. Give the result of each iteration to 4 decimal places. [exp(x) is an alternative notation for eˣ.][3]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2024). The mark or mark type is shown in brackets.
- [M1] Use the iterative process correctly at least once I.e., obtain one value and substitute that value back into the formula.
- [A1] Obtain final answer 8.03
- [A1] Show sufficient iterations to at least 4 decimal places to justify 8.03 to 2 decimal places, or show that there is a sign change in the interval (8.025,8.035) E.g. 7, 8.4555, 7.8846, 8.0849, 8.0115, 8.0380, 8.0283, 8.0318 8, 8.0421, 8.0268, 8.0324, 9, 7.7172, 8.1490, 7.9887, 8.0463, 8.0253, 8.0329
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