The variables x and y satisfy the equation a^(2y) = e^(3x+k), where a and k are constants. The graph of y against x is a straight line.
- (a)Use logarithms to show that the gradient of the straight line is (3 / (2 ln a)).[1]
- (b)Given that the straight line passes through the points (0.4, 0.95) and (3.3, 3.80), find the values of a and k.[4]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2024). The mark or mark type is shown in brackets.
- [B1] AG – necessary detail needed.
- [M1] Equate 3/(2 ln a) to gradient of line
- [A1] Obtain a = 4.6 or a = e^(29/19) or equivalent and hence obtain a = 4.6 or a = e^(2.85/2.9)
- [M1] Substitute appropriate values to find value of k
- [A1] Obtain k=1.7
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