Skip to main content
A-LevelMathematicsProbability and statistics9709/53 · Oct/Nov 2023 · Q410 Marks

The weights, xkg, of 120 students in a sports college are recorded. The results are summarised in the following table. Weight (xkg) | x ≤ 40 | x ≤ 60 | x ≤ 65 | x ≤ 70 | x ≤ 85 | x ≤ 100 Cumulative frequency | 0 | 14 | 38 | 60 | 106 | 120

  1. (a)Draw a cumulative frequency graph to represent this information.[2]
  2. (b)It is found that 35% of the students weigh more than Wkg. Use your graph to estimate the value of W.[2]
  3. (c)Calculate estimates for the mean and standard deviation of the weights of the 120 students.[6]

This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.

Mark scheme

Marking points from the official mark scheme (Oct/Nov 2023). The mark or mark type is shown in brackets.

  1. [M1] At least 3 points plotted accurately at class upper end points (40,0) (60,14) (65,38) (70,60) (85,106) (100,120). Linear cumulative frequency scale 0 < cf < 120 and linear weight scale 40 < weight(kg) ≤ 100 with at least 3 values identified on each axis. Condone scale reversed.
  2. [A1] All points plotted correctly, curve drawn (within tolerance) and joined to (40,0). Axes labelled cumulative frequency (cf), weight (w) and kg (kilograms) – or a suitable title.
  3. [M1] [120 × 0.65 = ] 78 seen May be implied by use on graph.
  4. [A1] 75 < hours < 79. Indication of use of graph required.
  5. [B1] At least 5 correct frequencies seen (condone omission of 0).
  6. [B1] At least 5 correct midpoints seen (condone omission of 20).
  7. [M1] Correct formula for mean using their midpoints and their frequencies, implied by 8545/120 if correct midpoints & frequencies seen. May be gained in variance calculation. If midpoints not clearly identified, condone midpoints ±0.5.
  8. [A1] Accept 1709/24 or 71 5/24 or 71.208333 to at least 3SF. If M0 scored, SC B1 for 1709/24 or 71 5/24 or 71.208333 to at least 3SF www.
  9. [M1] Correct formula for variance using their midpoints, their frequencies and their mean. Implied by 625062.5/120 - (8545/120)² if correct midpoints & frequencies seen.
  10. [A1] 11.757016 to at least 3SF.

Write your answer and get it marked

On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.

Sign up free →

About this question

Topic
Probability and statistics, A-Level Mathematics (syllabus 9709). Structured question, 10 marks.
Source
A-Level Mathematics, Oct/Nov 2023 Paper 5 Variant 3, question 4.

Questions and mark schemes are from past examination papers and remain the copyright of the exam board. How Oracle Prep builds its content

Related Mathematics questions

© 2026 Oracle Prep