Find the number of different arrangements of the 9 letters in the word ANDROMEDA in which no consonant is next to another consonant. (The letters D, M, N and R are consonants and the letters A, E and O are not consonants.)
- (a)Find the number of different arrangements of the 9 letters in the word ANDROMEDA in which no consonant is next to another consonant. (The letters D, M, N and R are consonants and the letters A, E and O are not consonants.)[3]
- (b)Find the number of different arrangements of the 9 letters in the word ANDROMEDA in which there is an A at each end and the Ds are not together.[3]
- (c)Four letters are selected at random from the 9 letters in the word ANDROMEDA. Find the probability that this selection contains at least one D and exactly one A.[4]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2023). The mark or mark type is shown in brackets.
- [M1] 5! x 4! / e. e a positive integer, 1 can be implied. No other terms on numerator. No addition etc.
- [M1] f / (2! x g!). f a positive integer, g = 1, 2. No other terms on denominator.
- [A1] 720.
- [B1] 7! / 2! - 6!. e, P_s - e, e a positive integer or 0.
- [M1] 6! / d!, d! > 720, r = 1, 2.
- [A1] 1800.
- [M1] At least one correct unsimplified expression for an identified scenario.
- [A1] [Total = ] 40 + 10 or 50 soi. If M0 scored, SC B1 [total =]50 www.
- [B1] [Total number of selections =] 9C4 [= 126]. Accept evaluated, accept as denominator of probability expression. Do not condone C5 unless there is a clear explanation for selecting the letters not in the group.
- [B1 FT] 0.396825... to at least 3SF. FT their attempted 40+10 / 126. Numerator must be from an attempt to find the 2 appropriate scenarios and must be evaluated.
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