A red spinner has four sides labelled 1, 2, 3, 4. When the spinner is spun, the score is the number on the side on which it lands. The random variable X denotes this score. The probability distribution table for X is given below. x | 1 | 2 | 3 | 4 P(X = x) | 0.28 | p | 2p | 3p A fair blue spinner and a fair green spinner each have four sides labelled 1, 2, 3, 4. All three spinners (red, blue and green) are spun at the same time.
- (a)Show that p = 0.12.[1]
- (b)Find the probability that the sum of the three scores is 4 or less.[3]
- (c)Find the probability that the product of the three scores is 4 or less given that X is odd.[5]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2023). The mark or mark type is shown in brackets.
- [B1] Using sum of probabilities = 1 to form an equation. Accept 0.28 + p + 2p + 3p = 1, p = 0.12. Substitution of 0.12 into the expression scores B0.
- [B1] Correct probability for 1 identified scenario, accept unsimplified, www.
- [M1] Add values of 4 correct scenarios, may be implied by correct unsimplified expressions. No incorrect/repeated scenarios.
- [A1] If A0 scored, SC B1 for 0.06 www.
- [B1] Seen alone or as the denominator of a conditional probability fraction. Accept unsimplified.
- [M1] Values of at least 5 identified correct scenarios added, accept unsimplified, condone incorrect scenarios in calculation.
- [M1] 0.28×(0.25)²xx+0.24×(0.25)², or 0.0175 × x + 0.015 where x = 4, 5, 6, 7, or 8. Seen alone or as numerator/denominator of a conditional probability fraction.
- [A1] 0.2980769... to at least 3SF.
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