A particle P of mass 0.2kg lies at rest on a rough horizontal plane. A horizontal force of 1.2N is applied to P.

Mark scheme

Marking points from the official mark scheme (Oct/Nov 2023). The mark or mark type is shown in brackets.

1. [B1] R = 0.2g
2. [M1] 1.2 = µ×0.2g Resolve horizontally and using F = µR to get an equation in µ; 2 relevant terms.
3. [A1] µ = 0.6 oe
4. [M1] 1.2-0.3×0.2g= 0.2a Resolve horizontally using Newton's Second Law; 3 relevant terms; allow sign errors; R = 0.2g only.
5. [A1] a=3 0.6=0.2a only seen, allow with BOD, but if 0.6 as friction being used as resultant force, this is M0A0.
6. [DM1] S3 = 0+½×3×3² [=13.5] S2 = 0+½×3×2² [=6] For use of s = ut + ½ at² (or a complete method) to find a distance at least once with u = 0 and their positive a and t=2 or t=3.
7. [A1] Distance = 13.5-6=7.5 m www