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A-LevelMathematicsTrigonometry9709/31 · Oct/Nov 2023 · Q56 Marks

Given that sin(x + π/3) – sin(x – π/3) = cos(x + π/3) – cos(x – π/3), find the exact value of tan x.

  1. (a)Given that sin(x + π/3) – sin(x – π/3) = cos(x + π/3) – cos(x – π/3), find the exact value of tan x.[4]
  2. (b)Hence find the exact roots of the equation sin(x + π/3) – sin(x – π/3) = cos(x + π/3) – cos(x – π/3) for 0 ≤ x ≤ 2π.[2]

Mark scheme

Marking points from the official mark scheme (Oct/Nov 2023). The mark or mark type is shown in brackets.

  1. [M1] (a) Use correct trig formulae and obtain an equation in sin x and cos x Allow one sign error.
  2. [A1] (a) Obtain a correct equation in any form e.g. 2cosxsin(π/3) = -2sinx sin(π/3).
  3. [DM1] (a) Substitute exact trig ratios and obtain an expression for tan x Allow one sign error.
  4. [A1] (a) Obtain answer tan x = -1/√3 Or exact equivalent.
  5. [B1] (b) Obtain answer, e.g. x = 5π/6
  6. [B1FT] (b) Obtain second answer, e.g. x = 11π/6 and no others in the interval FT first answer + π (provided 0 < first answer ≤ π). Or FT first answer – π (provided π < first answer ≤ 2π). Ignore any answers outside interval.

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About this question

Topic
Trigonometry, A-Level Mathematics (syllabus 9709). Structured question, 6 marks.
Source
A-Level Mathematics, Oct/Nov 2023 Paper 3 Variant 1, question 5.

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