The coordinates of points A, B and C are (6, 4), (p, 7) and (14, 18) respectively, where p is a constant. The line AB is perpendicular to the line BC.
- (a)Given that p < 10, find the value of p.[4]
- (b)A circle passes through the points A, B and C. Find the equation of the circle.[3]
- (c)Find the equation of the tangent to the circle at C, giving the answer in the form dx + ey + f = 0, where d, e and f are integers.[3]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2023). The mark or mark type is shown in brackets.
- [*M1] Their gradients must both come from (Difference in the ys / Difference in the xs) OR Scalar product leading to (14-p)(6-p)-33=0.
- [A1] Clearing of fractions and collecting terms to arrive at the three-term quadratic. Allow integer multiples.
- [DM1] OE Solving their three-term quadratic.
- [A1] If M1A1DM0 scored then SC B1 is available for final answer.
- [B1] SOI by final answer.
- [M1] Finding half of the length of AC or using their centre, which cannot be A, B or C, to find r² or r. Note: r=65 is M0.
- [A1] (x-6)(x-14)+(y-4)(y-18)=0 scores 3/3.
- [*M1] Gradient of their centre, which cannot be A, B or C, from part (b), to A or C or the gradient of AC but working needed if incorrect centre. OR by clearly differentiating and substitution of (14,18).
- [DM1] OE Using (14,18) and -1/their 7/4 to form the equation of a straight line.
- [A1] All terms on one side in any order. Allow multiples of this format by an integer only.
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