The probability distribution table for a random variable X is shown below. x -2 -1 0.5 1 2 P(X = x) 0.12 p q 0.16 0.3 Given that E(X) = 0.28, find the value of p and the value of q.
- Given that E(X) = 0.28, find the value of p and the value of q.[4]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2022). The mark or mark type is shown in brackets.
- [B1] Sum of probabilities = 1 p + q = 0.42 OE.
- [B1] Form equation using E(X) = 0.28 -p + 0.5q = -0.24 OE. Accept unsimplified.
- [M1] Either Substitution method to form a single equation in either p or q and finding values for both unknowns. Or Elimination method by writing both equations in the same form (usually ap + bq = c) and + or to find an equation in one unknown and finding values for both unknowns.
- [A1] CAO, both WWW. If M0 awarded SC B1 for both correct WWW.
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →