The times, in minutes, that Karli spends each day on social media are normally distributed with mean 125 and standard deviation 24.
- (a)(i)On how many days of the year (365 days) would you expect Karli to spend more than 142 minutes on social media?[5]
- (a)(ii)Find the probability that Karli spends more than 142 minutes on social media on fewer than 2 of 10 randomly chosen days.[3]
- (b)On 90% of days, Karli spends more than t minutes on social media. Find the value of t.[3]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2021). The mark or mark type is shown in brackets.
- [M1] Substitution of correct values into the Standardisation formula, allow continuity correction, not σ², √σ.
- [M1] Appropriate numerical area Φ, from final process, must be probability, expect p < 0.5.
- [A1] 0.239 < p < 0.240 to at least 3sf.
- [M1 FT] their 4sf (or better) probability.
- [A1 FT] Final answer must be positive integer, no indication of approximation/rounding, only dependent on previous M mark. SC B1 FT for their 3sf probability × 365 = integer value, condone 0.24 used.
- [M1] One term: 10Cxp* (1 – p)10-x for 0 < x < 10, any p.
- [A1 FT] Correct unsimplified expression using their probability to at least 3sf from (a)(i) or correct.
- [A1] AWRT, WWW.
- [B1] z = ±1.282 Correct value only, critical value.
- [M1] Use of Standardisation formula with correct values substituted, allow continuity correction, σ², √σ, to form an equation with a z-value and not probability.
- [A1] AWRT, condone AWRT 94.3. Not dependent on B mark.
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