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A-LevelMathematicsAlgebra9709/32 · Oct/Nov 2021 · Q24 Marks

Solve the inequality |3x – a| > 2|x + 2a|, where a is a positive constant.

  1. Solve the inequality |3x – a| > 2|x + 2a|, where a is a positive constant.[4]

Mark scheme

Marking points from the official mark scheme (Oct/Nov 2021). The mark or mark type is shown in brackets.

  1. [B1] State or imply non-modular inequality (3x−a)² > 2² (x+2a)², or corresponding quadratic equation, or pair of linear equations or linear inequalities
  2. [M1] Make reasonable attempt to solve a 3-term quadratic, or solve two linear equations for x in terms of a
  3. [A1] Obtain critical values x = 5a and x = −3/5 a and no others
  4. [A1] State final answer x > 5a, x < −3/5 a
  5. Alternative method for Question 2
  6. [B1] Obtain critical value x = 5a from a graphical method, or by solving a linear equation or linear inequality
  7. [B2] Obtain critical value x = −3/5 a similarly
  8. [B1] State final answer x > 5a, x < −3/5 a

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About this question

Topic
Algebra, A-Level Mathematics (syllabus 9709). Structured question, 4 marks.
Source
A-Level Mathematics, Oct/Nov 2021 Paper 3 Variant 2, question 2.

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